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leetcode-day-8

LeetCode 30 days Challenge - Day 8

本系列将对LeetCode新推出的30天算法挑战进行总结记录,旨在记录学习成果、方便未来查阅,同时望为广大网友提供帮助。


Middle of the Linked List

Given a non-empty, singly linked list with head node head, return a middle node of linked list.

If there are two middle nodes, return the second middle node.

Example 1:

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Input: [1,2,3,4,5]
Output: Node 3 from this list (Serialization: [3,4,5])
The returned node has value 3. (The judge's serialization of this node is [3,4,5]).
Note that we returned a ListNode object ans, such that:
ans.val = 3, ans.next.val = 4, ans.next.next.val = 5, and ans.next.next.next = NULL.

Example 2:

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Input: [1,2,3,4,5,6]
Output: Node 4 from this list (Serialization: [4,5,6])
Since the list has two middle nodes with values 3 and 4, we return the second one.

Note:

  • The number of nodes in the given list will be between 1 and 100.

Solution

题目要求分析:给定一个非空链表的头指针,返回这个链表在中间位置的结点。

解法:

典型例题,常常使用快慢指针来定位链表中部。

快指针一次步进2个结点,慢指针一次步进1个结点。当快指针到达末尾,慢指针正好到达链表中部。


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/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
ListNode* middleNode(ListNode* head) {
ListNode* fast = head, * slow = head;
while (fast && fast->next) {
slow = slow->next;
fast = fast->next->next;
}
return slow;
}

传送门:Middle of the Linked List

Karl